A wire that is 0.45 m long and carrying a current of 8.6 A is at right angles to a uniform magnetic field. The force on the wire is 0.40 N. What is the strength of the magnetic field?
- FiremanLv 73 months agoFavorite Answer
By F = iLBsinθ
=>0.40 = 8.6 x 0.45 x B x sin90*
=>B = 0.10 T
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