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Lance asked in Science & MathematicsPhysics · 2 months ago

What is the bullet's initial speed?

A bullet of mass 4.6 g strikes a ballistic pendulum of mass 3.1 kg. The center of mass of the pendulum rises a vertical distance of 6.5 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

2 Answers

  • Anonymous
    2 months ago

    work it backwards

    PE came from KE

    mgh = ½mv^2

    v = √(2gh) = √(2*9.8*0.065) m/sec = 1.13 m/sec

    conservation of momentum shall apply

    4.6g*V = 3104.6g*1.13m/sec

    V = 762 m/s

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  • Anonymous
    2 months ago

    PE at the top of the arc = (4.6 g + 3.1 kg) * g * 0.065 m

    KE at the bottom of the arc right after the bullet embeds itself is the same, solve for v.  KE = 1/2 * mass * speed^2


    To calculate the speed of the bullet, use conservation of momentum

    speed of bullet * mass of bullet = ((4.6 g + 3.1 kg) * speed from the above step.

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