# What is the resulting speed of the block? What is the speed of the bullet-block center of mass?

A 5.10 g bullet moving at 924 m/s strikes a 980 g wooden block at rest on a frictionless surface. The bullet emerges, traveling in the same direction with its speed reduced to 415 m/s. (a) What is the resulting speed of the block? (b) What is the speed of the bullet-block center of mass?

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- NCSLv 72 months agoFavorite Answer
(a) conserve momentum horizontally:

5.10g*924m/s = 5.10g*415m/s + 980g*V

V = 2.65 m/s

(b) Vcm = 5.10g*924m/s / (5.10+980)g = 4.78 m/s

Hope this helps!

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