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ziba asked in Science & MathematicsChemistry · 2 months ago

5) The first-order rearrangement propane is measured to have a rate constant of 2.85 × 10-11 s-1 at 298 K ?

and a rate constant of 6.36 × 10-6 s-1 at 400 K. Determine the activation energy for this reaction.

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  • 2 months ago
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    log(k2/k1)=Ea/2.303R[T2-T1/T2*T1]

    log(6.36 x 10^-6/2.85 x 10^-11)=Ea/2.303*8.314JK^-1mol^-1[400-298/400*298]

    Ea=7781.67mol^-1

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