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Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Need help please, keep trying it out using different methods but can't figure it out?

The reaction

2X(g) + 3Y(g) = 2Z(g) Kc=0.0164M^-3

occurs at 435 K. Calculate Kp of the reaction at 435 K. 

Answer in atm^-3

1 Answer

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  • Fern
    Lv 7
    1 month ago
    Favorite Answer

    Kp = Kc(RT)^Dn

    R = 0.08206 liter-atm/moleK

    T = Kelvin temperature

    Dn is the difference in the number of moles of gases on each side of the balanced equation for the reaction.

    Dn = (number of moles of gaseous products - number of moles of gaseous reactants)

    2X(g) + 3Y(g) ==⇒ 2Z(g)

    Dn = 2 -5 = -3

    Kp = (0.0164)[0.08206(435)]^-3

    Kp = (0.0164[35.7]^-3

    Kp = 0.0164(2.20 x 10^-5)

    Kp = 3.60 x 10^-7

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