Need help please, keep trying it out using different methods but can't figure it out?
2X(g) + 3Y(g) = 2Z(g) Kc=0.0164M^-3
occurs at 435 K. Calculate Kp of the reaction at 435 K.
Answer in atm^-3
- FernLv 71 month agoFavorite Answer
Kp = Kc(RT)^Dn
R = 0.08206 liter-atm/moleK
T = Kelvin temperature
Dn is the difference in the number of moles of gases on each side of the balanced equation for the reaction.
Dn = (number of moles of gaseous products - number of moles of gaseous reactants)
2X(g) + 3Y(g) ==⇒ 2Z(g)
Dn = 2 -5 = -3
Kp = (0.0164)[0.08206(435)]^-3
Kp = (0.0164[35.7]^-3
Kp = 0.0164(2.20 x 10^-5)
Kp = 3.60 x 10^-7