# physics webassin?

Suppose that a public address system emits sound uniformly in all directions and that there are no reflections. The intensity at a location 26 m away from the sound source is 3.2 10-4 W/m2. What is the intensity at a spot that is 74 m away?

In W/m2

Update:

the 3.2 10-4 w/m^2 means 3.2 times 10^-4

### 1 Answer

Relevance

- Anonymous1 month ago
inverse-square-of-distance applies

I = 3.2x10^-4 * (26/74)² = 3.95x10^-5 W/m^2

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