Calculate the allele frequencies?
For the following example curly versus straight hair is a single gene, 2 allele trait. That means that a single gene determines this trait in an organism. The two alleles for the trait are 'a' and 'A'. 'a' is the recessive allele coding for curly hair; and 'A' is the dominant allele coding for straight hair.
The following is the genotype distribution of a hypothetical population.
50 people - heterozygous; 30 - homozygous dominant, and 20 - homozygous recessive.
Calculate the allele frequencies for this population, such as f(a) and f(A).
Calculate the actual genotype frequency for the population, such as f(aA), f(AA), and f(aa).
Calculate the actual phenotype frequency for the population, such as f(curly) and f(straight).
- CRRLv 71 month ago
where q is the frequency of the recessive allele, q^2=20/100
- JazSincLv 71 month ago
This is a "count the alleles" problem.
Your total population is 50+30+20 = 100 individuals
Your population has a total of 200 alleles (there are enough clues in the way the question is worded to assume that this is a diploid species.)
Let q = f(a) = (50 + 20 + 20) / 200 = 0.45 (answer)
Let p = f(A) = (50 + 30 + 30)/200 = 110/200 = 0.55 (answer)
Actual genotype frequency:
f(aA) = 50/100 = 0.50
f(AA) = 30/100 = 0.30
f(aa) = 20/100 = 0.20
f(curly) = 20/100 = 0.20
f(straight) = (50 + 30)/100 = 0.80