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Anonymous asked in Science & MathematicsPhysics · 1 month ago

Physics help pleasee asap?

Standing on planet v that has a radius of 2*10^5.

5kg of my food has been release from rest at a height of 4m

it takes 4s to reach the surface

what will the gravitational acceleration of my food be while falling?

what is the mass of the planet?

3 Answers

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  • NCS
    Lv 7
    1 month ago

    a) from h = ½gt²

    we get

    g = 2h / t² = 2*4m / (4s)² = 0.5 m/s²

    b) Newton's Law of Gravitation:

    g = GM / r²

    so

    0.5 m/s² = 6.674e−11N·m²/kg² * M / (2E5m)²

    means that

    mass M = 3E20 kg

    as long as the units on your radius was "meters."

    If the units are "kilometers," then M = 3E26 kg.

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  • 1 month ago

    1) for the planet acceleration due to gravity is

    g = 2h / t’2 = 2x4 / 16 = 0.5 m/sec’2

    2) mass of the planet M = g R’2 / G = 0.5 x 4x10’10 / 6.67x10’-11 = 3x10’20 kg.

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  • oubaas
    Lv 7
    1 month ago

    2h = g*t^2

    g = 2h/t^2 = 8/4^2 = 0.5 m/sec^2 = M*G/r^2

    M = 0.5*4*10^10*10^11/6.674 = 3.00*10^20 kg

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