promotion image of download ymail app
Promoted
123 asked in Science & MathematicsPhysics · 1 month ago

Bill uniformly slows down from 15.0 m/s to 0 m/s in 2.50 s How many m b fore a stop sign must apply breaks. just a practice prob?

1 Answer

Relevance
  • Anonymous
    1 month ago

    distance d = ΔV*t/2 = (15-0)*2.5 / 2 = 7.5*2.5 = 18.75 m

    or

    distance d = (0-V^2) / (2*(0-V)/t) = -(15^2) / (-30/2.5) = -225*-2.5/30 = 18.75 m

    or

    distance d = V*t+(0-V)/2t*t^2 = V*t-15/5*2.5^2 = 15*2.5-3*6.25 = 18.75 m

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.