physics help with quadrants?
Assume: in the y (vertical) direction: up is positive; in the x (north-south) direction: north is positive.
Henry drives his car north at velocity 37.5 m/s, passing Annabelle, the stationary observer, standing on a street corner. If Annabelle sees rain falling straight down at constant velocity -37.4 m/s: find the angle at which Henry sees the rain fall.
HINT: According to Henry: in which quadrant does the rain fall?
- RealProLv 71 month ago
find the angle at which Henry sees the rain fall.
Has no one taught you the importance of using the absence of detail to your advantage?
Henry sees the rain fall at an angle 20° clockwise of the direction 20° anticlockwise from the direction of falling rain.
What was your question? This is as simple as it can possibly get.
The vertical velocity of rain is the same for Henry as it is for Annabelle.
The horizontal is 37.5 m/s south because he's driving 37.5 m/s north.
The vector (-37.5, -37.4) is at an angle arctan(37.4 / 37.5) = 44.924° from the negative x-axis toward the negative y-axis or at a standard polar angle of 224.924° which you can round as required.
I suggest you contact the author of the exercise and tell them to cut the crap with confusing numbers.