# A) Calculate the work done on or by the helium gas in joules (J). B) What is the change in the helium’s internal energy in kilojoules (kJ)?

A total of 22.6 kJ of heat energy is added to a 6.05L sample of helium at 0.986atm. The gas is allowed to expand against a fixed external pressure to a volume of 24.5L.

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- Roger the MoleLv 71 month ago
A)

(24.5 - 6.05)L x (0.986 atm x (101.325 kPa/atm)) = 1843 J = -1.843 kJ

(The last minus sign shows that the work was done by the He on the surroundings.)

B)

ΔE = +22.6 kJ - 1.843 kJ = +20.8 kJ

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