A) Calculate the work done on or by the helium gas in joules (J). B) What is the change in the helium’s internal energy in kilojoules (kJ)?
A total of 22.6 kJ of heat energy is added to a 6.05L sample of helium at 0.986atm. The gas is allowed to expand against a fixed external pressure to a volume of 24.5L.
- Roger the MoleLv 71 month ago
(24.5 - 6.05)L x (0.986 atm x (101.325 kPa/atm)) = 1843 J = -1.843 kJ
(The last minus sign shows that the work was done by the He on the surroundings.)
ΔE = +22.6 kJ - 1.843 kJ = +20.8 kJ