# finding terms and sequences?

Hi, I'm not good with this kind of stuff. Can anyone help with it?

write the first four terms of the sequence: a(sub n) = (-1)^n+1(n+5)

### 5 Answers

- Engr. RonaldLv 71 month ago
an = (-1)^(n+1) * (n + 5)

a₁ = (-1)^(1 + 1) * (1 + 5) = 6

a₂ = (-1)^(2 + 1) * (2 + 5) = -7

a₃ = (-1)^(3 + 1) *(3 + 5) = 8

a₄ = (-1)^(4 + 1)*(4 + 5) = -9

The 1st four therms of the sequence are: 6,-7,8,-9 ..... answer//

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- Wayne DeguManLv 71 month ago
I assume you mean a(n) = (-1)⁽ⁿ ⁺ ¹⁾[n + 5]

i.e. a(1) => (-1)²(6)

and a(2) => (-1)³(7)....e.t.c.

:)>

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- ?Lv 71 month ago
n a(sub n)

-----.......--------------------------

0............(-1)⁰+1(0+5) = 1+5 = 6

1........... (-1)¹+1(1+5) = -1 + 6 = 5

2........... (-1)²+1(2+5) = 1 + 7 = 8

3........... (-1)³+1(3+5) = -1 + 8 = 7

4........... (-1)⁴+1(4+5) = 1 + 9 = 10

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- ted sLv 71 month ago
you cannot replace ' n ' with 1 , then 2 , then 3 , then 4 , etc ?

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- rotchmLv 71 month ago
a(0) = (-1)^(n+1) * (n+5) with n=0. What you get?

a(1) = (-1)^(n+1) * (n+5) with n=1. What you get?

Etc.

Answer the above if need be and we will proceed.

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