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Anonymous asked in Science & MathematicsChemistry · 1 month ago

Chem question--will award best answer?

At 100 ∘C, Kc=0.078 for the reaction

SO2Cl2(g)←→SO2(g)+Cl2(g)

In an equilibrium mixture of three gases, the concentrations of SO2Cl2 2 and SO2 are 0.140 M and 0.13 M respectively.

What is the partial pressure of Cl2 in the equilibrium mixture?

The answer isnt .69 M

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  • 1 month ago
    Favorite Answer

    Someone asked this same question yesterday here: https://answers.yahoo.com/question/index?qid=20200...

    Pisga... calculated the molarity of Cl2 gas at equilibrium. The question asked for the partial pressure of Cl2. There was an error made in that calculation. The correct calculation is here:

    Again, assume you have 1 L of gas. Then,

    PV = n RT

    P = 0.084 mol (0.08206 Latm/molK) (373 K) / 1 L = 2.57 atm

    • pisgahchemist
      Lv 7
      1 month agoReport

      Ooops.  Too used to just finding concentration. Thanks for finishing the solution to problem.

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  • 1 month ago

    Chemical equilibrium ....

    SO2Cl2(g) <==> SO2(g) + Cl2(g) .............. Kc = 0.078

    0.140M .............. 0.130M ....xM ................. equilibrium

    Kc = [SO2][Cl2] / [SO2Cl2]

    0.078 = 0.130x / 0.140

    x = 0.084

    [Cl2] = 0.084M

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