Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

# Chem question--will award best answer?

At 100 ∘C, Kc=0.078 for the reaction

SO2Cl2(g)←→SO2(g)+Cl2(g)

In an equilibrium mixture of three gases, the concentrations of SO2Cl2 2 and SO2 are 0.140 M and 0.13 M respectively.

What is the partial pressure of Cl2 in the equilibrium mixture?

Relevance
• 1 month ago

Pisga... calculated the molarity of Cl2 gas at equilibrium. The question asked for the partial pressure of Cl2. There was an error made in that calculation. The correct calculation is here:

Again, assume you have 1 L of gas. Then,

PV = n RT

P = 0.084 mol (0.08206 Latm/molK) (373 K) / 1 L = 2.57 atm

• pisgahchemist
Lv 7
1 month agoReport

Ooops.  Too used to just finding concentration. Thanks for finishing the solution to problem.

• 1 month ago

Chemical equilibrium ....

SO2Cl2(g) <==> SO2(g) + Cl2(g) .............. Kc = 0.078

0.140M .............. 0.130M ....xM ................. equilibrium

Kc = [SO2][Cl2] / [SO2Cl2]

0.078 = 0.130x / 0.140

x = 0.084

[Cl2] = 0.084M