# carey bought 8 tickets for \$52 how many tickets could she purchase with \$90?

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• 90x8/52 =  13.84

so carey can buy 13 tickets

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• Anonymous
1 month ago

13 tickets.

52 ÷ 8 = 6.5

So each ticket is \$6.50. Now divide 90 by 6.50. You get 13.

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• At \$52.00 for 8 tickets, each ticket costs \$6.50, so at \$90.00 it's 13.84615384615385 or 13 tickets.

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• Carey bought 8 tickets for \$52.

The cost of one ticket is \$6.50

She could purchase 13 tickets with \$90

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• 52 divided by 8 = ? Now divide 90 by what you got for ?

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• Anonymous
2 months ago

use a ratio.  Let X be the number of tickets you want to find out.

X / \$90 = 8 / \$52

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• Ticket Price (P) = 52/8

Number of tickets she could purchase (T) = 90/P

Those are your two equations, sub the 1st into the 2nd and solve for T

T = 90/(52/8)

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• 52 / 8 = \$6.50

So 13 tickets.

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