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carey bought 8 tickets for $52 how many tickets could she purchase with $90?

8 Answers

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  • 1 month ago

    90x8/52 =  13.84 

    so carey can buy 13 tickets 

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  • Anonymous
    1 month ago

    13 tickets.

    52 ÷ 8 = 6.5

    So each ticket is $6.50. Now divide 90 by 6.50. You get 13.

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  • 2 months ago

    At $52.00 for 8 tickets, each ticket costs $6.50, so at $90.00 it's 13.84615384615385 or 13 tickets.

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  • 2 months ago

    Carey bought 8 tickets for $52. 

    The cost of one ticket is $6.50

    She could purchase 13 tickets with $90

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  • 2 months ago

    52 divided by 8 = ? Now divide 90 by what you got for ?

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  • Anonymous
    2 months ago

    use a ratio.  Let X be the number of tickets you want to find out.

    X / $90 = 8 / $52

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  • 2 months ago

    Ticket Price (P) = 52/8

    Number of tickets she could purchase (T) = 90/P

    Those are your two equations, sub the 1st into the 2nd and solve for T

    T = 90/(52/8)

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  • .
    Lv 7
    2 months ago

    52 / 8 = $6.50

    So 13 tickets.

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