# carey bought 8 tickets for $52 how many tickets could she purchase with $90?

### 8 Answers

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- Anonymous1 month ago
13 tickets.

52 ÷ 8 = 6.5

So each ticket is $6.50. Now divide 90 by 6.50. You get 13.

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- MICHAEL KLv 72 months ago
At $52.00 for 8 tickets, each ticket costs $6.50, so at $90.00 it's 13.84615384615385 or 13 tickets.

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- KrishnamurthyLv 72 months ago
Carey bought 8 tickets for $52.

The cost of one ticket is $6.50

She could purchase 13 tickets with $90

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- Elaine MLv 72 months ago
52 divided by 8 = ? Now divide 90 by what you got for ?

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- Anonymous2 months ago
use a ratio. Let X be the number of tickets you want to find out.

X / $90 = 8 / $52

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- StarShineLv 72 months ago
Ticket Price (P) = 52/8

Number of tickets she could purchase (T) = 90/P

Those are your two equations, sub the 1st into the 2nd and solve for T

T = 90/(52/8)

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