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Titration of 30mL of 0.08M acetic acid solution with 0.0850M KOH. What's the analytical concentration of acetate ions at equivalence point?

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  • 2 months ago

    Supposing the potassium acetate ionizes completely:

    (30 mL) x (0.08M acetic acid) x (1 mol acetate / 1 mol acetic acid) / (58 mL) =

    0.041 M acetate

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