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Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Physic Help........?

A tiny ball (mass = 0.013 kg) carries a charge of -17 μC. What is the electric field magnitude that would cause the ball to float above the ground?

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  • 2 months ago

    set forces equal

    F = w = mg = QE

    E = mg/Q = (0.013 kg)(9.8) / (17e-6) = 7490 V/M

    Electric field

    The strength or magnitude of the field at a given point

    is defined as the force that would be exerted on a

    positive test charge of 1 coulomb placed at that point;

    the direction of the field is given by the direction of

    that force.

       E = F/Q = kQ/r²

       Q = F/E F = QE

    in Newtons/coulomb OR volts/meter

       k = 1/4πε₀ = 8.99e9 Nm²/C²

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