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# In Denver, children bring their old jack-o-lanterns to the top of a tower and compete for accuracy in hitting a target on the ground...?

Suppose that the tower height is h = 10.80 m, and that the bulls-eye's horizontal distance is d = 3.9 m from the launch point. If the pumpkin is thrown horizontally, what is the launch speed needed to hit the bulls-eye? (Neglect air resistance.)

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- stanschimLv 72 months agoFavorite Answer
d = (1/2)(a)(t^2) = 10.80 = (1/2)(9.81)(t^2).

Time to hit the ground, t = 1.48 s.

Horizontally, d = vt.

v = d / t = 3.9 / 1.48 = 2.63 m/s.

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