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Anonymous
Anonymous asked in Science & MathematicsAgriculture · 2 months ago

Help me solve this equation ?

x^2 = (x+3)/2

6 Answers

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  • 2 months ago

    x^2 = (x + 3)/2

    2x^2 = x + 3

    2x^2 - x - 3 = 0

    (2x - 3)(x + 1) = 0

    x = 3/2 or x = -1

    • Lv 4
      2 months agoReport

      good clear answer

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  • 2 months ago

    2x^2 = x + 3

    2x^2 - x - 3 = 0

    (2x - 3)(x + 1) = 0

    2x - 3 = 0

    x = 3/2 = 1.5

    &

    x + 1 = 0

    x = -1

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  • Lôn
    Lv 7
    2 months ago

    2x^2 = x + 3

    2x^2 - x - 3 = 0

    2x^2 - 3x + 2x - 3 = 0

    x (2x - 3) + 1 (2x - 3 ) = 0

    (x + 1)(2x - 3) = 0

    Either x + 1 = 0 ..... x = -1

    Or 2x - 3 = 0...... x = 3/2

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  • 2 months ago

    Multiplying by 2 we get:

    2x² = x + 3

    Re-arranging we get:

    2x² - x - 3 = 0

    Then factorising gives:

    (2x - 3)(x + 1) = 0

    Hence, x = 3/2 or x = -1

    :)>

    • Lv 4
      2 months agoReport

      very good answer

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  • 2 months ago

    Multiply both sides by 2:

    2x² = x + 3

    Get everything on one side:

    2x² - x - 3 = 0

    Factor:

    2x² - 3x + 2x - 3 = 0

    x(2x - 3) + 1(2x - 3) = 0

    (x + 1)(2x - 3) = 0

    Set those each to zero:

    x + 1 = 0

    x = -1

    or

    2x - 3 = 0

    2x = 3

    x = 3/2

    x = 1½

    Answer:

    x = -1 or x = 1½

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  • 2 months ago

    x²=½(x+3)

    2x²=(x+3)

    2x²-x-3=0

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