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# How do you solve for x in: ln(3)=ln(10)-(0.1)(x)?

### 4 Answers

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- stanschimLv 71 month agoFavorite Answer
Solve just like any equation:

ln(3) = ln(10) - (0.1)(x)

-0.1x = [ln(3) - ln(10)]

x = [ln(3) - ln(10)] / -0.1 = 12.03972804

- PhilipLv 61 month ago
ln(3) = ln(10) - (0.1)x, ie. ln(10) - ln(3) = ln(10/3) = (0.1)x. Multiply through

bt 10 getting x = 10ln(10/3) = 10(1.203972804) = 12.0397804.

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- VamanLv 71 month ago
ln(3)=ln(10)-(0.1)(x)?

0.1x = ln 10 -ln 3=ln 10/3

10/3= e^(0.1x) =e^(x/10)

x = 10 ln(10/3)=12.04

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- ?Lv 71 month ago
ln(3) = ln(10) - (0.1)(x) ⇒

0.1x = ln 10 - ln 3

.......ln 10 - ln 3

x = ---------------

............0.1

......2.30259 - 1.09861

x = ------------------------

............0.1

x = 12.0398......................ANS

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I simply subtracted ln(10) from each side and wrote the equation with the terms reversed from the original problem. Remember, try to isolate the unknown, x, on the left side of the equation when doing algebra.