Hi asked in Science & MathematicsMathematics · 1 month ago

How do you solve for x in: ln(3)=ln(10)-(0.1)(x)?

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  • 1 month ago
    Favorite Answer

    Solve just like any equation:

    ln(3) = ln(10) - (0.1)(x)

    -0.1x = [ln(3) - ln(10)]

    x = [ln(3) - ln(10)] / -0.1 = 12.03972804

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    • stanschim
      Lv 7
      1 month agoReport

      I simply subtracted ln(10) from each side and wrote the equation with the terms reversed from the original problem.  Remember, try to isolate the unknown, x, on the left side of the equation when doing algebra.

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  • Philip
    Lv 6
    1 month ago

    ln(3) = ln(10) - (0.1)x, ie. ln(10) - ln(3) = ln(10/3) = (0.1)x. Multiply through

    bt 10 getting x = 10ln(10/3) = 10(1.203972804) = 12.0397804.

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  • Vaman
    Lv 7
    1 month ago

    ln(3)=ln(10)-(0.1)(x)?

    0.1x = ln 10 -ln 3=ln 10/3

    10/3= e^(0.1x) =e^(x/10)

    x = 10 ln(10/3)=12.04

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  • ?
    Lv 7
    1 month ago

    ln(3) =  ln(10) - (0.1)(x) ⇒

    0.1x = ln 10 - ln 3

    .......ln 10 - ln 3

    x = ---------------

    ............0.1

    ......2.30259 - 1.09861

    x = ------------------------

    ............0.1

    x = 12.0398......................ANS

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