H2 (g) + I2 (g) -> 2 HI (g) Using [H2], the instantaneous rate at 50 s is: Using [HI], the instantaneous rate at 50 s is?
- pisgahchemistLv 74 weeks ago
H2(g) + I2(g) <==> 2HI(g)
The rate of appearance of HI is twice the rate of disappearance of H2.
Rate = -Δ[H2] / Δt = (1/2)Δ[HI] / Δt
The instantaneous rate at time "t" is the slope of the line which is tangent to curve at time "t."
Slope = Δy/Δx
rate (H2) = -0.28M / 40s = -0.0070 M/s
rate (HI) = 0.56M / 40s = 0.014 M/s