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# The half-lives of different radioisotopes are given in the table.?

The half-lives of different radioisotopes are given in the table.

Radioisotope Half-life (min)

argon-44

12

lead-196

37

potassium-44

22

indium-117

43

If the initial amount of argon-44 is

9.6 g, how much argon-44 is left in the body after

24 min?

### 3 Answers

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- SpacemanLv 73 weeks ago
t½ = half-life of argon-44 = 12 min

λ = [lambda] radioactive decay constant = to be determined

λ = ln (2) / t½

λ = 0.693147 / 24

λ = 0.057762265

N0 = original amount of argon-44 = 9.6 g

t = decay time = 24 min

Nt = amount of argon-44 after t min = to be determined

Nt = N0·e^(-λ·t)

Nt = 9.6 g·e^(-0.057762·24)

Nt = 2.4 g ANSWER

Source(s): https://www.1728.org/halflif2.htm https://socratic.org/questions/what-is-the-half-li... http://www.softschools.com/formulas/chemistry/radi...- Login to reply the answers

- Anonymous3 weeks ago
24 min = 2 half lives = 1/4 of the original amount remaining. 9.6 g / 4 = mass of Ar remaining.

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