Need help with Chemistry question please!! How many moles of water are produced by this neutralization?
Consider the neutralization between the following two solutions:
100.0 mL 0.9285 M hydrochloric acid, HCl
150.0 mL 1.8269 M sodium hydroxide, NaOH
How many moles of water are produced by this neutralization?
- Roger the MoleLv 72 months ago
HCl + NaOH → NaCl + H2O [balanced as written]
(100.0 mL x 0.9285 M HCl) = 92.85 mmol HCl
(150.0 mL x 1.8269 M NaOH) = 274.035 mmol NaOH
92.85 millimoles of HCl would react completely with 92.85 millimoles of NaOH, but there is more NaOH present than that, so NaOH is in excess and HCl is the limiting reactant.
(92.85 mmol HCl) x (1 mol H2O / 1 mol HCl) = 92.85 mmol H2O = 0.09285 mol H2O