Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

calc help?

integration help 

integral of (e^(sqrt5y-9))/(sqrt5y-9) dy

2 Answers

Relevance
  • Vaman
    Lv 7
    1 month ago

    x=sqrt(5y-9)

    dx=1/sqrt(5y-9) 2/5

    You have2/5 e^x dx. The integral will be 2/5 e^x+c= 2/5 e^(sqrt(5y-9))+c

    • Login to reply the answers
  • u = sqrt(5y - 9)

    u^2 = 5y - 9

    2u * du = 5 * dy

    du = 5 * dy / (2 * u)

    du = 5 * dy / (2 * sqrt(5y - 9))

    (2/5) * du = dy / sqrt(5y - 9)

    e^(sqrt(5y - 9)) * dy / sqrt(5y - 9) =>

    e^(u) * (2/5) * du

    Integrate

    (2/5) * e^(u) + C =>

    (2/5) * e^sqrt(5y - 9) + C

    • Login to reply the answers
Still have questions? Get your answers by asking now.