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# calc help?

integration help

integral of (e^(sqrt5y-9))/(sqrt5y-9) dy

### 2 Answers

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- VamanLv 71 month ago
x=sqrt(5y-9)

dx=1/sqrt(5y-9) 2/5

You have2/5 e^x dx. The integral will be 2/5 e^x+c= 2/5 e^(sqrt(5y-9))+c

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- 1 month ago
u = sqrt(5y - 9)

u^2 = 5y - 9

2u * du = 5 * dy

du = 5 * dy / (2 * u)

du = 5 * dy / (2 * sqrt(5y - 9))

(2/5) * du = dy / sqrt(5y - 9)

e^(sqrt(5y - 9)) * dy / sqrt(5y - 9) =>

e^(u) * (2/5) * du

Integrate

(2/5) * e^(u) + C =>

(2/5) * e^sqrt(5y - 9) + C

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