If the terminal arm of angle θ intersects the unit circle at point (-7/9, (-sqrt32)/9) then what is θ to the nearest hundredth of a radian?

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  • 1 month ago
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    you want the arctan ((√32/9) / (7/9))

    θ = arctan ((√32/9) x (9/7))

    θ = arctan (4√2/7)

    θ = 0.68 rad

    but this is in Q3 as both are negative, so

    θ = π + 0.68 rad = 3.82 rad

    edit, corrected

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