- SamwiseLv 74 weeks ago
I'm not sure why we'd want to "make a chart,"
but perhaps if I show you an algebraic solution,
your class experience will suggest a suitable chart.
Let a represent the quantity of solution A, in liters,
and b represent the quantity of solution B.
Then we can write the equations
a + b = 4 [describing the total quantity of solution]
0.08a + 0.20b = 0.11 (4) [describing the acetic acid percentage]
to represent the problem.
We can simplify that second equation, dividing each side by 0.04 to obtain
2a + 5b = 11
and then find the common solution. Subtracting twice the first equation yields
3b = 3
b = 1
which leads quickly to the answer, that we combine
3 liters of solution A (contributing 0.24 liters acetic acid)
1 liter of solution B (contributing 0.20 liters acetic acid)
to obtain 4 liters of solution with 0.44 liters (11%) acetic acid.
Back to the chart question: Perhaps you could make a table with different quantities of each solution and calculate the acid percentage in each.
- Roger the MoleLv 74 weeks ago
Let z be the volume of Solution A (in liters) to be found.
Then the volume of Solution B is (4 - z) liters.
(0.08 z) + (0.20 (4 - z)) = 4 (0.11)
Solve for z algebraically:
z = 3 liters Solution A
4 - z = 1 liter Solution B
Make the chart yourself.