need help physics?
An 89 kg fisherman jumps from a dock
into a 140 kg rowboat at rest on the West side
of the dock.
If the velocity of the fisherman is 4.3 m/s
to the West as he leaves the dock, what is the
final velocity of the fisherman and the boat?
Answer in units of m/s.
Note: Take East as the positive direction.
- billrussell42Lv 71 month agoFavorite Answer
initial momentum = 89•4.3 kgm/s
final momentum = (89+140)V
set them equal
(89+140)V = 89•4.3
229V = 382.7
V = 1.67 m/s
same direction as fisherman, to the west.