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Half of Deborah’s poker chips are from Bally’s, one-fourth of her chips are from MGM?

Half of Deborah’s poker chips are from Bally’s, one-fourth of her chips are from MGM, she has an equal number of chips from Caesars, Harrahs, and Mirage. If Deborah has 7 chips from the Mirage, how many chips does she have altogether?   

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  • Alan
    Lv 7
    2 months ago
    Favorite Answer

    Let x = totals chips she  has 

    B = (1/2)x   

    MGM= (1/4) x

    she has 7 chips from each Caesars, Harrah, and the mirage

    3*7 = 21  

    so if this is all the chips she has  

    B + MGM = x((1/2) + (1/4)) = 3/4(x) 

    (3/4)x  + 21   =  x   

    x - (3/4)x =  21 

    (1/4) x = 21 

    x = 4*21 = 84 chips in total 

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  • DEBS
    Lv 7
    2 months ago

    M=H=C.

    C=7 thus M+H+C=21 which we know is 1/4 of her total chips. 

          .(1/2 are B, 1/4 are MGM leaving 1/4 for M+H+C).

    .

    Thus, 21*4 = 84.

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