Physics help? ?
A 50.0 N box is at rest on a horizontal surface. The coefficient of static friction between the box and the surface is .5, and the coefficient of kinetic friction is 0.30. A horizontal 20.0 N force is then exerted on the box. What is it's acceleration?
- billrussell42Lv 74 weeks agoFavorite Answer
once it starts moving, kinetic friction is all that matters, as long as the applied force is enough to overcome the static friction
force of kinetic friction = 0.3x50 = 15 N
force of static friction = 0.5x50 = 25 N
20 N is not enough to overcome the static friction, so the box does not move, acceleration = 0
- oubaasLv 74 weeks ago
Since μs = 0.5 and weight*μs = 50*0.5 = 25 N > 20 N, then the box won't move