Jon asked in Science & MathematicsPhysics · 4 weeks ago

Physics help? ?

A 50.0 N box is at rest on a horizontal surface. The coefficient of static friction between the box and the surface is .5, and the coefficient of kinetic friction is 0.30. A horizontal 20.0 N force is then exerted on the box. What is it's acceleration?

2 Answers

  • 4 weeks ago
    Favorite Answer

    once it starts moving, kinetic friction is all that matters, as long as the applied force is enough to overcome the static friction

    force of kinetic friction = 0.3x50 = 15 N

    force of static friction = 0.5x50 = 25 N

    20 N is not enough to overcome the static friction, so the box does not move, acceleration = 0

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  • oubaas
    Lv 7
    4 weeks ago

    Since μs = 0.5 and weight*μs = 50*0.5 = 25 N > 20 N, then the box won't move

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