Please help me on this question, i couldnt get it right, help me understand by explaining some of your answers.?
Two cars A and B have a velocity of 100kph in some direction. Car A is 35m behind car B, when the brakes are applied to car B causing it to decelerate at a rate of 4m/s^2 . In what time will car A overtakes car B? How far did car A has traveled ?
- Anonymous1 month ago
V*t = V*t-1/2a*t^2+35
a*t^2 = 70
t = √70/4 = 4.183 sec
dA = V*t = 100/3.6*4.183 = 116.2 m