Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

you decomposed 2.000g of MgSO4 . 7H2O. after heating the sample to constant mass, ?

Suppose you decomposed 2.000g of MgSO4 . 7H2O. after heating the sample to constant mass, the remaining residue in the crucible weighs 0.978g. what is the mass of water lost and mass percent of water in the hydrate? please provide steps. 

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  • 1 month ago

    Hydrated salt ....

    MgSO4•7H2O(s) --> MgSO4(s) + 7H2O(g)

    2.000g ................. ........0 ................ 0

    .....0 ..................... ....0.978g.......... 1.022g  ........ subtract

    Percent of water = 1.022 / 2.000 x 100 = 51.10%

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  • Anonymous
    1 month ago

    When you heat the material, the water is driven off.  The mass of water is just the difference.  I certainly hope you can do percentages.

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