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# you decomposed 2.000g of MgSO4 . 7H2O. after heating the sample to constant mass, ?

Suppose you decomposed 2.000g of MgSO4 . 7H2O. after heating the sample to constant mass, the remaining residue in the crucible weighs 0.978g. what is the mass of water lost and mass percent of water in the hydrate? please provide steps.

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- pisgahchemistLv 71 month ago
Hydrated salt ....

MgSO4•7H2O(s) --> MgSO4(s) + 7H2O(g)

2.000g ................. ........0 ................ 0

.....0 ..................... ....0.978g.......... 1.022g ........ subtract

Percent of water = 1.022 / 2.000 x 100 = 51.10%

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- Anonymous1 month ago
When you heat the material, the water is driven off. The mass of water is just the difference. I certainly hope you can do percentages.

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