Lizzie asked in Science & MathematicsPhysics Β· 1 month ago

The acceleration of an object after t seconds is π‘Ž(𝑑)=𝑑^(2)+2ms^(βˆ’2). If the velocity at t=2 was 3 ms^(βˆ’1), what was the velocity at t=4?

The acceleration of an object after t seconds is π‘Ž(𝑑)=𝑑^(2)+2ms^(βˆ’2). If the velocity at t=2 was 3 ms^(βˆ’1), what was the velocity at t=4?

2 Answers

Relevance
  • rotchm
    Lv 7
    1 month ago

    Note that your notation is "crap".Β  A much better way to write your question is :

    " The acceleration of an object after t seconds is a(𝑑)=𝑑^2+2. If the velocity at t=2 was 3 , what was the velocity at t=4? "Β  You don't need to indicate the units here since its meant to be standard. And even if you have to write them, its not "𝑑^(2)+2ms^(βˆ’2)" but rather " ( t^2 + 2 ) m/s^2 ". Do learn to write clearly.Β 

    Now, let's move on... You know that ∫ a = v.  IOW,

    So, whats the ∫ of your a(t) ?  Answer that & we will proceed. 

    • Login to reply the answers
  • 1 month ago

    dv/dt = a

    v(4) - v(2) = int[2 to 4] a(t) dt

    Finish him.

    • Login to reply the answers
Still have questions? Get your answers by asking now.