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# The acceleration of an object after t seconds is π(π‘)=π‘^(2)+2ms^(β2). If the velocity at t=2 was 3 ms^(β1), what was the velocity at t=4?

The acceleration of an object after t seconds is π(π‘)=π‘^(2)+2ms^(β2). If the velocity at t=2 was 3 ms^(β1), what was the velocity at t=4?

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- rotchmLv 71 month ago
Note that your notation is "crap".Β A much better way to write your question is :

" The acceleration of an object after t seconds is a(π‘)=π‘^2+2. If the velocity at t=2 was 3 , what was the velocity at t=4? "Β You don't need to indicate the units here since its meant to be standard. And even if you have to write them, its not "π‘^(2)+2ms^(β2)" but rather " ( t^2 + 2 ) m/s^2 ". Do learn to write clearly.Β

Now, let's move on... You know that β« a = v.Β IOW,

So, whats the β« of your a(t) ?Β Answer that & we will proceed.Β

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- RealProLv 71 month ago
dv/dt = a

v(4) - v(2) = int[2 to 4] a(t) dt

Finish him.

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