Given y a x where y is 6 and x is 2, find y when x is 7?
- davidLv 74 weeks ago
y a x where y is 6 and x is 2, find y when x is 7?
I will guess that y a x .. is y is directly proportional to x
y/x = y/x
6/2 = y/7 <<< solve for y
y = 21 <<< answer
- billrussell42Lv 74 weeks ago
y a x ?? what does this mean ?
- ted sLv 74 weeks ago
21would be a reasonable answer if you are measuring linearly
- az_lenderLv 74 weeks ago
If you were trying to say y is proportional to x, then the answer is
7*(6/2) = 21.
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- L. E. GantLv 74 weeks ago
need a bit more information...
like suppose y = x + 4 then y = 6 when x = 2 and hence y = 11 when x = 7
but suppose y = x^2 + 2 then y = 6 when x = 2 and y = 51 when x = 7
- alexLv 74 weeks ago
assume y ∝ xthat is y = kx , with constant k≠0
- PuzzlingLv 74 weeks ago
I'm not sure of your notation (y a x). I believe you are trying to say that y is directly proportional to x:
y ∝ x
Another way to write that is:
y = kx, where k is a constant of proportionality.
We are given one case when y = 6 and x = 2, so plug those in and solve for k:
6 = k * 2
6/2 = k
k = 3
So the final equation is:
y = 3x
That basically says that the value of y is 3 times the value of x.
Now we can easily figure out any x or y, given the other variable. For example, when x = 7
y = 3(7)
y = 21
y = 21