How many moles of diphenylmethanol can be produced by reacting 0.55 grams of benzophenone with an excess of sodium borohydride?
- Roger the MoleLv 71 month ago
1 mole of benzophenone ((C6H5)2CO) produces
1 mole of diphenylmethanol ((C6H5)2CHOH), so:
(0.55 g (C6H5)2CO) / (182.217 g (C6H5)2CO/mol) x
(1 mol (C6H5)2CHOH / 1 mol (C6H5)2CO) x (184.238 g (C6H5)2CHOH/mol) =
0.56 g (C6H5)2CHOH
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