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# How do you find the energy required to change 49.0g of ice at 0.0°C to steam at 100.0°C?

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- NCSLv 71 month ago
energy = mass * (heat of fusion + specific heat*temperature change + heat of vaporization)

so the answer depends on what you take for your heat values.

For heat of fusion = 334000 J/kg

and specific heat of water = 4186 J/kg·ºC

and heat of vaporization = 2256000 J/kg

I get

E = 1.47e5 J = 147 kJ

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