The height y (in feet) of a ball thrown by a child is y=1/14X^2+4x+5
where x is the horizontal distance in feet from the point at which the ball is thrown.
(a) How high is the ball when it leaves the child's hand?
(b) What is the maximum height of the ball?
(c) How far from the child does the ball strike the ground?
- M.P.Lv 51 month ago
Let me see now...that's y=1/14X^2+4x+5 multiplied by pi squared, plus the height/velocity of the ball thrown, that would land the ball at about...half way between you and the kid or by the tree, because children have really bad aim and super week arms!