How many grams of hydrated MgSO 4 ⋅ 5 H 20 (M.W.: MgSO 4 = 119, H 20 = 18) are required to make a 10% solution of MgS0 4?
Please help this utterly lost chemistry student!
- Anonymous1 month ago
As Roger said, you don't have enough information. Let's assume they want 1 L of 10% m/v solution.
10% m/v of 1 L = 100 g of MgSO4 (you don't leave a space between the O and the 4).
Since the MgSO4 exists as MgSO4-5H2O, you need 100 g * ((119 + 5 * 18)/119 g) = mass of the hydrate.
Of course, if you want 100 mL of 0.1 M, the answer is going to be totally different.
- Roger the MoleLv 71 month ago
It depends on:
1) How much solution do you need?
2) What kind of percent are we talking about here? mass? moles?