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# WHAT IS THE LIMIT?

Limit as x approaches 2 f(x)= what

IF f(2)=5 and x can only be 4,3,1, or 0.

### 4 Answers

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- Iggy RockoLv 71 month ago
Since the domain includes neither 2 nor a sequence approaching 2,

lim f(x) does not exist

x -> 2

- MyRankLv 61 month ago
Limt(x→2) f(x) = ?

f(2) = 5

Limt (x→2) f(2) = 5

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- ted sLv 71 month ago
if the domain of f(x) is { 0,1,3,4 } then lim { x---> 2 } f(x) does not exist , NOR does f(2) = 5...since 2 is not in the domain

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Even if 2 did exist in the domain, pick epsilon = 1/2. Then, there is no delta such that |2 - x| < delta implies |5 - f(x)| for x in the domain, I believe.