Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

# Math Problem?

Lazlo and Rupa ride their bicycles from Winnipeg to St. Pierre-Jolys, a distance of 54 km, and back. They are somewhat tired o the return trip, and ride 4km/hr slower than they did for the first part of their ride. Their trip takes 5hrs, counting a 3 min stop for a drink. How fast did they travel on the outbound trip?

Relevance
• 1 month ago

Lazlo and Rupa ride their bicycles

from Winnipeg to St. Pierre-Jolys, a distance of 54 km, and back.

They are somewhat tired of the return trip,

and ride 4 km/hr slower than they did for the first part of their ride.

Total distance is 108 km.

Their trip takes 5 hrs, counting a 3 min stop for a drink.

Their trip takes 4 hours 57 minutes.

54/x + 54/(x - 4) = 4.95

54(x - 4) + 54x = 4.95x(x - 4)

4.95x^2

How fast did they travel on the outbound trip?

• alex
Lv 7
1 month ago

5hrs - 3 min = 4h57min = 99/20 hours

the outbound speed = x km/h

---> the return speed = (x-4) km/h

Time = distance / speed

54/x + 54/(x-4) = 99/20

solve for x