PLZ HELP STOICHIOMETRY HOMEWORK?
4) carbon disulfide is an important industrial solvent. It is prepared by the reaction of coke with sully dioxide
5C (s) + 2SO2 (g) —> CS2 (s) + 4CO (g)
A. How many moles of CS2 form when 6.30 mol it C reacts?
B. How many moles of carbon are needed to react with 7.24 mol of SO2?
5) how many grams of CO2 will be produced when 8.50g of methane react with 15.9f of O2, according to the following reaction?
CH4 (g) + 2O2 (g) —> CO2 (g) + 2H2O
- Roger the MoleLv 71 month ago
(6.30 mol C) x (1 mol CS2 / 5 mol C) = 1.26 mol CS2
(7.24 mol SO2) x (5 mol C / 2 mol SO2) = 18.1 mol C
(8.50 g CH4) / (16.0425 g CH4/mol) = 0.5298 mol CH4
(15.9 g O2) / (31.99886 g O2/mol) = 0.49689 mol O2
0.49689 mole of O2 would react completely with 0.49689 x (1/2) = 0.248445 mole of CH4, but there is more CH4 present than that, so CH4 is in excess and O2 is the limiting reactant.
(0.49689 mol O2) x (1 mol CO2 / 2 mol O2) x (44.00964 g CO2/mol) = 10.9 g CO2