the potential difference across two plates is 1.50 V. If the plates are 8.22*10^-4 m apart, what is the electric field between them?
- Anonymous1 month agoFavorite Answer
The field can be expressed in V/m (or N/C), so one might reasonably guess that
field = potential / distance
E = 1.50V / 8.22*10^-4m = 1.82*10*3 V/m (or N/C)
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