what is the equation for tge line that passes through the points (-5,2) and (5,-6)?

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  • David
    Lv 7
    2 days ago

    Points: (-5, 2) and (5, -6)

    Slope: -5/4

    Equation: y = -4/5x -2

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  • 2 days ago

    given two points, (-5,2) and (5,-6),

    FIRST find the SLOPE, m.

    m = (2+6)/(-5-5) = -8/10 = -4/5

    now use point-slope form:

    y - 2 = (-4/5)(x + 5)

    simplify to point slope form:

    y = (-4/5)x + -4 + 2

    y = (-4/5)x - 2

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  • 2 days ago

    Point 1

    (-5, 2)

    Point 2

    (5, -6)

    First find the slope

    m = rise/run

    m = (y₂ - y₁) / (x₂ - x₁)

    m = (-6 - 2) / (5 - -5)

    m = -8 / 10

    m = -4/5 

    --------------------

    Plug in one of the points (-5, 2) and m = -4/5

    into slope intercept form to find "b"

    y = mx + b

    2 = (-4/5)(-5) + b

    2 = 4 + b

    b = -2

    ------------------

    using m = -4/5  and b = -2 the equation becomes

    y = (-4/5)x - 2 <––––––

     

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