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# what is the equation for tge line that passes through the points (-5,2) and (5,-6)?

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- DavidLv 72 days ago
Points: (-5, 2) and (5, -6)

Slope: -5/4

Equation: y = -4/5x -2

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- Marley KLv 72 days ago
given two points, (-5,2) and (5,-6),

FIRST find the SLOPE, m.

m = (2+6)/(-5-5) = -8/10 = -4/5

now use point-slope form:

y - 2 = (-4/5)(x + 5)

simplify to point slope form:

y = (-4/5)x + -4 + 2

y = (-4/5)x - 2

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- MichaelLv 72 days ago
Point 1

(-5, 2)

Point 2

(5, -6)

First find the slope

m = rise/run

m = (y₂ - y₁) / (x₂ - x₁)

m = (-6 - 2) / (5 - -5)

m = -8 / 10

m = -4/5

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Plug in one of the points (-5, 2) and m = -4/5

into slope intercept form to find "b"

y = mx + b

2 = (-4/5)(-5) + b

2 = 4 + b

b = -2

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using m = -4/5 and b = -2 the equation becomes

y = (-4/5)x - 2 <––––––

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