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# Find the sample variance and standard deviation.?

(22, 10, 4, 6, 11)

A. s^2=

B. s=

### 1 Answer

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- 1 month ago
Find the mean:

(4 + 6 + 10 + 11 + 22) / 5 =>

(10 + 10 + 33) / 5 =>

53 / 5 =>

10.6

Now, find the difference between each term and the mean

10.6 - 4 = 6.6

10.6 - 6 = 4.6

10.6 - 10 = 0.6

10.6 - 11 = -0.4

10.6 - 22 = -11.4

Square each difference and sum those squares

6.6^2 + 4.6^2 + 0.6^2 + (-0.4)^2 + (-11.4)^2 =>

43.56 + 21.16 + 0.36 + 0.16 + 129.96 =>

195.2

Find the mean of that sum

195.2 / 5 =>

39.04

That's the variance. The standard deviation will be the square root of that

39.04 =>

3904 / 100 =>

976 / 25 =>

16 * 61 / 25

sqrt(16 * 61 / 25) =>

4 * sqrt(61) / 5 =>

6.2481997407253235153037781886073

6.248, roughly

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Yeah, you're supposed to.