the square of a number is 6 more than the number. find the number.?

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  • Como
    Lv 7
    1 month ago

    -

    x²  =  x  +  6

    x²  -  x  -  6  = 0

    ( x  - 3 ) ( x. + 2 ) = 0

    x.  = 3 , x   = - 2

    The number could be 3 or - 2

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  • 1 month ago

    the answer is 3.

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  • 1 month ago

    x^2 = x + 6

    x^2 - x - 6 = 0

    (x - 3)(x + 2) = 0

    x = 3 or x = -2

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  • 1 month ago

    x^2 = x + 6

    (x - 3)(x + 2) = 0

    x = -2

    x = 3

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  • David
    Lv 7
    1 month ago

    The number is 3 because 3^2 = 3+6

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  • sepia
    Lv 7
    1 month ago

    x^2 - x - 6 = 0

    (x - 3)(x + 2) = 0

    x = -2  

    x = 3

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  • 1 month ago

    A^2=A+6

    A=3     3*3=9, 3+6=9

    A=  -2  -2*-2=4,  -2+6=4

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  • 1 month ago

    The number is N

    the square of the number

    N-squared

    is 6 more than the number

    N + 6 = N-squared

    You can set it equal to zero

    0 = N-squared - N - 6

    and then use the binomial equation

    or factor

    Factoring

    we get

    0 = (N - 3)(N + 2)

    So

    N is EITHER

    +3

    or

    -2

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  • x^2 = x + 6

    x^2 - x - 6 = 0

    x = (1 +/- sqrt(1 + 24)) / 2

    x = (1 +/- sqrt(25)) / 2

    x = (1 +/- 5) / 2

    x = -4/2 , 6/2

    x = -2 , 3

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  • 1 month ago

    The number is either 3 or -2.

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