How many liters of 0.300M FeI3 solution will react with 0.255moles of F2 according to this chemical equation: 3 F2 +2 FeI3--> 3 I2 + 2 FeF3?

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  • 1 month ago

    (0.255 mol F2) x (2 mol FeI3 / 3 mol F2) / (0.300 mol FeI3/L) = 0.567 L

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  • Anonymous
    1 month ago

    0.255 moles F2 will react with 2 / 3 * 0.255 moles of FeI3

     

    Liters = moles of FeI3 / 0.3 M

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