A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the pavement?
- az_lenderLv 71 month ago
v_final = at = (9.8 m/s^2)*(2 s) = 19.6 m/s.
- billrussell42Lv 71 month ago
v = gt = 9.8•2 = 19.6 m/s
falling object starting from rest
h is height in meters, t is time falling in seconds,
g is acceleration of gravity, usually 9.8 m/s²
v is velocity in m/s
h = ½gt²
t = √(2h/g)
v = √(2gh)
h = v²/2g
v = gt
- R RLv 41 month ago
Velocity = Distance / Time, find the velocity of a falling object that is traveling at the speed of gravity.