Anonymous asked in Science & MathematicsPhysics · 1 month ago

A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the pavement?

3 Answers

  • 1 month ago

    v_final = at = (9.8 m/s^2)*(2 s) = 19.6 m/s.

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  • 1 month ago

    v = gt = 9.8•2 = 19.6 m/s

    falling object starting from rest

    h is height in meters, t is time falling in seconds,

    g is acceleration of gravity, usually 9.8 m/s²

    v is velocity in m/s

    h = ½gt²

    t = √(2h/g)

    v = √(2gh)

    h = v²/2g

    v = gt

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  • R R
    Lv 4
    1 month ago

    Velocity = Distance / Time, find the velocity of a falling object that is traveling at the speed of gravity.

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