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# A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the pavement?

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- billrussell42Lv 71 month ago
v = gt = 9.8•2 = 19.6 m/s

falling object starting from rest

h is height in meters, t is time falling in seconds,

g is acceleration of gravity, usually 9.8 m/s²

v is velocity in m/s

h = ½gt²

t = √(2h/g)

v = √(2gh)

h = v²/2g

v = gt

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- R RLv 41 month ago
Velocity = Distance / Time, find the velocity of a falling object that is traveling at the speed of gravity.

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