physics help please?

A certain spring requires a force of 29 N to stretch it a distance of 0.45 m from its relaxed position. What is the elastic constant in N/m for this spring?

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  • MyRank
    Lv 6
    4 weeks ago

    Given,

    Force (F) = 29N 

    Distance (x) = 0.45m 

    Elastic constant (k) = ? 

    We know that:- 

    Force (F) = kx 

    Elastic constant (k) = force (F) / Distance (x) = 29N / 0.45m = 64.4N/m ≈ 64N/m ∴ Elastic constant (k) = 64N/m.

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  • 1 month ago

    Andrew. You do need to learn some formulae to get anywhere.  I don't believe that physics is JUST formula but without them you cannot even start. Definition of k = dF / dx ( change of force/ change in length)

    = 29 N / 0.45 m ~= 64 N/m  ( remember those significant figures lessons)

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  • Anonymous
    1 month ago

    Hooke's Law:

    F = k*x

    29N = k * 0.45m

    k = 64 N/m

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  • Anonymous
    1 month ago

    F = k /

     x = 64.4 N/m

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  • Fuhr
    Lv 6
    1 month ago

    Seven             .

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