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# physics help please?

A certain spring requires a force of 29 N to stretch it a distance of 0.45 m from its relaxed position. What is the elastic constant in N/m for this spring?

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- MyRankLv 64 weeks ago
Given,

Force (F) = 29N

Distance (x) = 0.45m

Elastic constant (k) = ?

We know that:-

Force (F) = kx

Elastic constant (k) = force (F) / Distance (x) = 29N / 0.45m = 64.4N/m ≈ 64N/m ∴ Elastic constant (k) = 64N/m.

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- Andrew SmithLv 71 month ago
Andrew. You do need to learn some formulae to get anywhere. I don't believe that physics is JUST formula but without them you cannot even start. Definition of k = dF / dx ( change of force/ change in length)

= 29 N / 0.45 m ~= 64 N/m ( remember those significant figures lessons)

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- Anonymous1 month ago
Hooke's Law:

F = k*x

29N = k * 0.45m

k = 64 N/m

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- Anonymous1 month ago
F = k /

x = 64.4 N/m

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