X^-1dy/dx = 2cos^2y, y(0) = 𝜋/4?

can i get the answer ASAP please?

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    dy / (x * dx) = 2 * cos(y)^2

    dy / cos(y)^2 = 2x * dx

    sec(y)^2 * dy = 2x * dx

    Integrate

    tan(y) = x^2 + C

    y = pi/4 when x = 0

    tan(pi/4) = 0^2 + C

    1 = 0 + C

    1 = C

    tan(y) = x^2 + 1

    y = arctan(x^2 + 1)

    • Nixon2 months agoReport

      Thank you so much sir :)

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