Anonymous asked in Science & MathematicsPhysics · 1 month ago

gr 12 physics?

A 31.0 kg child on a swing reaches a maximum height of 1.92 m above their rest position. Assuming no loss of energy: 

a) At what point during the swing will she attain their maximum speed?

b) What will be her maximum speed through the subsequent swing?

c) Assuming this maximum height was the result of one push from her parent, what was the average force exerted by the parent if they pushed over a distance of 152 cm?

4 Answers

  • 1 month ago
    Favorite Answer

    When the potential energy is a minimum the kinetic energy is a maximum. ie at the bottom of the swing.

    b) Ek = Ep -> 1/2 m v^2 = mgh-> v= sqrt( 2h*g) = sqrt( 2*1.92*9.8) m/s

    c) E = F.d -> mgh = F.d -> F = mgh/d= 31*9.8*1.92/1.52 N

  • 1 month ago

    Conservation of Energy

    When swing is at the lowest, the PE has become KE

    mgh = 1/2 m v^2

    So v = √(2gh)  so plug in numbers and solve, round to 3 sigfigs

    6.14 m/s

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  • Anonymous
    1 month ago


    at the lowest point of the swing


    V = √2gh = √19.612*1.92 = 6.14 m/sec


    m*g*h = F*d

    F = 31*9.806*1.92/1.52 = 384 N

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  • Anonymous
    1 month ago

    On Earth,  or the International Space Station, or on the Moon?

    • Raymond1 month agoReport

      its probably on earth but idk this guy shouldve been specific

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