A 5.0 kilogram mass is hung from a spring causing it to stretch 0.37 meters. What is the elastic constant of the spring?
- MyRankLv 61 month ago
Mass (m) = 5kg
Elongation (x) = 0.37m
Elastic constant of spring (k) = ?
Acceleration due to gravity (g) = 9.81m/sec²
We know that:-
Force (F) = kx
m x g = kx
k = (mg/x) = 5kg x 9.81m/sec² / 0.37m = 132.5N/m ≈ 133N/m ∴ Elastic constant (k) = 133N/m.Source(s): https://myrank.co.in/
- Anonymous1 month ago
k = m*g/x = 5*9.806/0.37 = 132.5 N/m
- Andrew SmithLv 71 month ago
I think you need to rub out your name on the top of the homework and put "done entirely by Yahoo Answers".