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# An airplane is flying in a horizontal circle at a speed of 103 m/s.?

The 73.0 kg pilot does not want the centripetal acceleration to exceed 6.45 times free-fall acceleration.

(A)Find the minimum radius of the plane’s

path. The acceleration due to gravity is 9.81m/s2. Answer in units of m.

(B)At this radius, what is the magnitude of the net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth?

Answer in units of N.

### 2 Answers

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- az_lenderLv 72 months agoFavorite Answer
(B) mv^2/r = m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator.

(A) v^2/r <= 6.45*g =>

r >= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2)

= around 15m but use a calculator.

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- oubaasLv 72 months ago
centripetal acceleration ca = 6.45*9.81 = 63.3 m/sec^2

radius r = V^2/ca = 103^2/63.3 = 168 m

centripetal force F = m*ca = 73*63.3 = 4620 N

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